sin^5x+cos^5x=-1,则sinx+cosx=?

2sin^2x - 5sin x cos x=3 cos^2x,求X, 已知sin x-cos x=1/5(0 已知sin x+cos x=-1/5(0 求方程 sin^3x+cos^5x=1 已知sin^2x-cos^2x=1/5,则tan^2x= 已知sin^2x-cos^2x=1/5,则tan^2x= 已知-π/2＜x＜0,sin x+cos x=1/5求sin 2x+2 sin 急,matlab解非线性方程组用什么函数呢 方程如下所示：(cos(x(1))*cos(x(3))-sin(x(1))*cos(x(2))*sin(x(3)))*(194-x(4))*x(7)+(cos(x(1))*sin(x(3))+sin(x(1))*cos(x(2))*cos(x(3)))*(145-x(5))*x(7)+sin(x(1))*sin(x(2))*x(6)*x(7)-1=0;(-sin(x(1 已知(1+sin x)/cos x=-1/2,则cos/(sin x-1)=? 已知sin[a-b]cos a-cos[b-a]sin a=3/5,b是第三象限角,求sin[b+5π/4]的值第一题1/2cos x-√3/2sin x第二题√3sin x+cos x第三题√2[sin x-cos x]第四题√2cos x-√6sin x sin(5x)-sin(3x)= 根号2cos(4x)1.sin(5x)-sin(3x)= （根号2）cos(4x)解方程2.sin（x）+sin(2x)+sin(3x)=1+cos(x)+cos(2x) 化简sin(x)(cos(x)+cos(3x)+cos(5x)+cos(7x)) 已知sin(π/2-x)+sin(π-x)/cos(-x)+sin(2π-x)=2009,则tan(x+5π/4)等于?已知sin(π/2-x)+sin(π-x)/cos(-x)+sin(2π-x)=2009,则tan(x+5π/4)等于（） A.-2009 B.-1/2009 C.1/2009 D.2009 sin^5x+cos^5x=-1,则sinx+cosx=? 一道数学题：sin（π+x）=1/5,则cos（π-x）=? 求导sin^5x*cos^5x (1+cos x-sin x)/(1-sin x-cos x)+(1-cos x-sin x)/(1-sin x+cos x)=? cos x/sin x+sin x/(1+cos x) 化简.