sin(x+y)-sinx=2siny/2·cos(x+y/2)怎么来的
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sin(x+y)-sinx=2siny/2·cos(x+y/2)怎么来的sin(x+y)-sinx=2siny/2·cos(x+y/2)怎么来的sin(x+y)-sinx=2siny/2·cos(x+
sin(x+y)-sinx=2siny/2·cos(x+y/2)怎么来的
sin(x+y)-sinx=2siny/2·cos(x+y/2)怎么来的
sin(x+y)-sinx=2siny/2·cos(x+y/2)怎么来的
sin(x+y)-sinx
=sin[(x+y/2)+y/2]-sin[(x+y/2)-y/2]
=sin(x+y/2)cos(y/2)+sin(y/2)cos(x+y/2) -[sin(x+y/2)cos(y/2)-cos(x+y/2)sin(y/2)]
=2siny/2·cos(x+y/2)
证明sin(x+y)sin(x-y)=sinx-siny
证明 [sin(2x+y)/sinx]-2cos(x+y)=siny/sinx
求证sin(2x+y)/sinx-2cos(x+y)=siny/sinx
求证:sin(2x+y)/sinx-2cos(x+y)=siny/sinx
证明sin(x+y)sin(x-y)=(sinx)^2-(siny)^2.
证明sinx+cos(x+y)siny/cosx-sin(x+y)siny=tan(x+y)
证明cosx(cosx-cosy)+sinx(sinx-siny)=2sin(x-y)/2
为什么sinx*cosy-cosx*siny=sin(x-y)
求函数z=sinx+siny+sin(x+y)(0
存在sin( x -y) = sinX-sinY吗
请问,如何证明sinx+siny=2*sin(x+y/2)*cos(x-y/2)
为什么sin(x+y) - sinx = 2cos(x+y/2)siny/2
求推导sinx-siny=2cos((x+y)/2)sin((x-y)/2)
求证sinx+siny=2sin(x+y)/2*cos(x-y)/2
求证:sinx+siny=2sin(x+y)/2cos(x-y)/2
求证|sinx-siny|=|2sin[(x-y)/2]cos[(x+y)/2]|
sin(x+y)-sinx=2siny/2·cos(x+y/2)怎么来的
arcsin(sinx+siny)+arc(sinx-siny)=kπ/2,K为奇数,求sin^2x+sin^2y的值