log2 27/log2 9=
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log227/log29=log227/log29=log227/log29=换底公式：logab/logac=logcb所以原式=log927=log3²3³=（3/2）*log
log2 27/log2 9=
log2 27/log2 9=
log2 27/log2 9=
换底公式：loga b/loga c=logc b
所以原式=log9 27
=log3² 3³
=（3/2）*log3 3
=3/2
log2 27/log2 9=
log2(3)×log2(4)=log2(7)?log2(3)×log2(4)=log2(7)吗?log2(1/49)+log2(1/16)+log2(1/27)等于多少呢?帮个忙!
(log2 9)/(log2 8) = 2/3(log2 3)
log2 (log2 16)=?
log2^(x^log2^x)=?
log2(log2
(log8 9/log2 3)=?
log2^x=log4^9
LOG2^3=A,LOG2^5=b,则log2^9/5值是多少
log4(log2^x)=log2(log4^x)求log2^x
2log2 10—log2 25=?
log2 5/4+log2 5=多少,
log2 (x+1)+log2 x=log6
（log2 27）×（log3 8）=?
log9(16) ×log2(27)=6步骤
log2^9*log3^8
log8(9)*log2(3)
9^log2(3) 求值