A/(x-5)+B/(x+2)=(5x-4)/(x的平方-3x-10)求A,B

来源:学生作业帮助网 编辑:六六作业网 时间:2024/05/11 14:36:40
A/(x-5)+B/(x+2)=(5x-4)/(x的平方-3x-10)求A,BA/(x-5)+B/(x+2)=(5x-4)/(x的平方-3x-10)求A,BA/(x-5)+B/(x+2)=(5x-4)

A/(x-5)+B/(x+2)=(5x-4)/(x的平方-3x-10)求A,B
A/(x-5)+B/(x+2)=(5x-4)/(x的平方-3x-10)求A,B

A/(x-5)+B/(x+2)=(5x-4)/(x的平方-3x-10)求A,B
左边通分=[A(x+2)+B(x-5)]/(x-5)(x+2)
=[(A+B)x+(2A-5B)]/(x-5)(x+2)
=(5x-4)/(x-5)(x+2)
则(A+B)x+(2A-5B)=5x-4
所以A+B=5
2A-5B=-4
A=3
B=2