设f(x)=ax^3+bx+1,并且f(-3)=2,则f(3)=

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设f(x)=ax^3+bx+1,并且f(-3)=2,则f(3)=设f(x)=ax^3+bx+1,并且f(-3)=2,则f(3)=设f(x)=ax^3+bx+1,并且f(-3)=2,则f(3)=f(x)

设f(x)=ax^3+bx+1,并且f(-3)=2,则f(3)=
设f(x)=ax^3+bx+1,并且f(-3)=2,则f(3)=

设f(x)=ax^3+bx+1,并且f(-3)=2,则f(3)=
f(x)=ax³+bx+1,
=> f(-3)=a×(-3)³+b×(-3)+1=2
=> 27a+3b=-1,
=> f(3)=a×3³+3b+1=27a+3b+1=-1+1=0

f(x)=ax³+bx+1,
=> f(-3)=a×(-3)³+b×(-3)+1=2
=> 27a+3b=-1,
=> f(3)=a×3³+3b+1=27a+3b+1=-1+1=0