设f(x,y)=e^(x^2+y^2) 则 f(x,kx)=?

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设f(x,y)=e^(x^2+y^2)则f(x,kx)=?设f(x,y)=e^(x^2+y^2)则f(x,kx)=?设f(x,y)=e^(x^2+y^2)则f(x,kx)=?f(x,kx)=e^[x^

设f(x,y)=e^(x^2+y^2) 则 f(x,kx)=?
设f(x,y)=e^(x^2+y^2) 则 f(x,kx)=?

设f(x,y)=e^(x^2+y^2) 则 f(x,kx)=?
f(x,kx)=e^[x^2+(kx)^2]