y=cos(2x+π/6)在[0,π/2]值域是

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y=cos(2x+π/6)在[0,π/2]值域是y=cos(2x+π/6)在[0,π/2]值域是y=cos(2x+π/6)在[0,π/2]值域是∵x∈[0,π/2],∴2x+π/6∈[π/6,7π/6

y=cos(2x+π/6)在[0,π/2]值域是
y=cos(2x+π/6)在[0,π/2]值域是

y=cos(2x+π/6)在[0,π/2]值域是
∵x∈[0,π/2],∴2x+π/6∈[π/6,7π/6]
∴cos(2x+π/6)∈[-√3/2,√3/2](余弦在这段范围内递减)
∴值域为:[-√3/2,√3/2]

值域是[-1,1] x=-π/12时,y=1 x=5π/12时,y=-1