高数：这个积分怎么求?如图
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高数：这个积分怎么求?如图高数：这个积分怎么求?如图高数：这个积分怎么求?如图剩下的应该容易解了.(2-u)/(u²-1)=(1/2)[1/(u-1)-3/(u+1)]∫[(2-u)/(u&
高数：这个积分怎么求?如图
高数：这个积分怎么求?
如图
高数：这个积分怎么求?如图
剩下的应该容易解了.
(2-u)/(u²-1)=(1/2)[1/(u-1) -3/(u+1)]
∫[(2-u)/(u²-1)]du
=∫(1/2)[1/(u-1) -3/(u+1)]du
=(1/2)∫[1/(u-1)]du -(3/2)∫[1/(u+1)]du
=(1/2)∫[1/(u-1)]d(u-1) -(3/2)∫[1/(u+1)]d(u+1)
=(...
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(2-u)/(u²-1)=(1/2)[1/(u-1) -3/(u+1)]
∫[(2-u)/(u²-1)]du
=∫(1/2)[1/(u-1) -3/(u+1)]du
=(1/2)∫[1/(u-1)]du -(3/2)∫[1/(u+1)]du
=(1/2)∫[1/(u-1)]d(u-1) -(3/2)∫[1/(u+1)]d(u+1)
=(1/2)ln|u-1| -(3/2)ln|u+1| +C
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