.(x+y-2)(x+y-2xy)+(xy-1)^2
来源：学生作业帮助网 编辑：六六作业网 时间：2024/05/09 19:26:26
.(x+y-2)(x+y-2xy)+(xy-1)^2.(x+y-2)(x+y-2xy)+(xy-1)^2.(x+y-2)(x+y-2xy)+(xy-1)^2令x=1得f(x,y)=0；知有因式（x-1
.(x+y-2)(x+y-2xy)+(xy-1)^2
.(x+y-2)(x+y-2xy)+(xy-1)^2
.(x+y-2)(x+y-2xy)+(xy-1)^2
令x=1得f(x,y)=0；
知有因式（x-1）,
代入x=1时得到 -（y-1）^2 + (y-1)^2
又x,y对称知有因式（y-1）
于是可以猜想（y-1）^2是因式,试验一下就知.
分解得(x-1)^2*(y-1)^2
df
(-x-y)(x^2+xy+y^2)
化简x^-y^/x^-2xy+y^
2*(x-y)²(y-x)(xy)
（x^2+xy/x-y)/（xy/x-y)计算
X-Y/2X+2Y XY/X+Y²
因式分解：x×x-xy-2y×y-x-y
(x+y)/x /(x-(2xy-y^2)/x) 因式分解
代数 x^-y^/ x^-(y-z)^ 除以 x^+2xy+y^/(x-y)^-z^ 乘 x^+xy-xz/x^-xy
因式分解:12xy^2(y-x)+xy^3(x-y)+4x^2y(x-y)
(x-y)[(x+y)^2-xy]+(x-y)[(x-y)^2+xy]
x根号x+x根号y/xy-y^2)-（x+根号xy+y/x根号x-y根号）y
.(x+y-2)(x+y-2xy)+(xy-1)^2
(x^2-xy)y÷y-x/xy怎么做?
[x(x^2y^2-xy)-y(x^2-x^3y)]/(2x^2y)
[x(x^2y^2-xy)-y(x^2-x^3y)]/3x^2y
[x(x^2y^2-xy)-y(x^2-x^3y)]/3x^2y
2xy/(x+y)(x+y)与x/(x+y)(x-y)怎么通分
(x+y)(x+y+2xy)+(xy+1)(xy-1)(x+y)(x-y)+4(y-1)