f(x+y,y/x)=x^2-y^2,求f(x,y),详见里面
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f(x+y,y/x)=x^2-y^2,求f(x,y),详见里面f(x+y,y/x)=x^2-y^2,求f(x,y),详见里面f(x+y,y/x)=x^2-y^2,求f(x,y),详见里面设u=x+y,
f(x+y,y/x)=x^2-y^2,求f(x,y),详见里面
f(x+y,y/x)=x^2-y^2,求f(x,y),详见里面
f(x+y,y/x)=x^2-y^2,求f(x,y),详见里面
设u=x+y, v=y/x
可以解出x=u/(v+1),y=uv/(v+1)
所以f(u,v)=[u/(v+1)]^2-[uv/(v+1)]^2=(1-v^2)u^2/(v+1)^2=(1-v)u^2/(1+v)
所以f(x,y)=(1-y)x^2/(1+y)
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