..complex number如果z=cis (Θ),证明z+1/z=2cos(Θ)注意下:条件是"cis"( cos(Θ)+i sin(Θ),不是"cos"

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..complexnumber如果z=cis(Θ),证明z+1/z=2cos(Θ)注意下:条件是"cis"(cos(Θ)+isin(Θ),不是"cos"..complexnumber如果z=cis(Θ

..complex number如果z=cis (Θ),证明z+1/z=2cos(Θ)注意下:条件是"cis"( cos(Θ)+i sin(Θ),不是"cos"
..complex number
如果z=cis (Θ),证明z+1/z=2cos(Θ)
注意下:条件是"cis"( cos(Θ)+i sin(Θ),不是"cos"

..complex number如果z=cis (Θ),证明z+1/z=2cos(Θ)注意下:条件是"cis"( cos(Θ)+i sin(Θ),不是"cos"
1/(cosΘ+isinΘ) 上下同乘(cosΘ-isinΘ),1/(cosΘ+isinΘ) =cosΘ-isinΘ
z+1/z=cosΘ+isinΘ +1/(cosΘ+isinΘ)= cosΘ+isinΘ+cosΘ-isinΘ =2cos(Θ)
即证

cis是什么…

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