y=cos(π/4+x)cos(π/4-x)+cos2x值域RT,
来源：学生作业帮助网 编辑：六六作业网 时间：2024/05/26 21:46:43
y=cos(π/4+x)cos(π/4-x)+cos2x值域RT,y=cos(π/4+x)cos(π/4-x)+cos2x值域RT,y=cos(π/4+x)cos(π/4-x)+cos2x值域RT,y
y=cos(π/4+x)cos(π/4-x)+cos2x值域RT,
y=cos(π/4+x)cos(π/4-x)+cos2x值域
RT,
y=cos(π/4+x)cos(π/4-x)+cos2x值域RT,
y=cos(π/4+x)cos(π/4-x)+cos2x
=cos(π/4+x)sin(x+π/4)+cos2x
=(1/2)sin(2x+π/2)+cos2x
=sin2x/2+cos2x
=√[(1/2)^2+1^2]sin(2x+θ)
=√5sin(2x+θ)/2
-√5/2
y=cos(π/4-x)求导
函数y=cos^2(π/4-x)-cos^2(π/4+x)的值域是
y=cos(π/4+x)cos(π/4-x)的单调递减区间
函数y=cos(x-π/4)cos(x+π/4)的值域是?
y=cos(π/4+x)cos(π/4-x)+cos2x值域RT,
求y=cos(π/4-x)的导数
Y=cos(3x-π/4)的导数
函数y=cos(2x+π/4) 求dy
求周期 y=2cos（2x- π/4)
函数y=cos(2x+π/4)的对称轴
函数y=sin(x)cos(x+ π/4)+cos(x)sin(x+π/4)的最小正周期是
y=3cos(2x+π/4) （2）y=2cos(x-π/6)的单调区间
若cos(x+y)=4/5,cos(x-y)=-4/5,且3π/2
求微分方程COS xSin ydy=COS y Sin xdx,Y|x=0 =π/4的特解
y=4cos(x/3),0
化简：cos(π/4-x)乘cos(π/4+x)
y=2cos(x/4+ π/3)-3sin(x- π/4)y=sin(4x- π/3)-cos(3x+π/2)
sin(x+y)cosx+cos(x+y)sinx=1/3 x∈(3π/2,2π) 求cos(2x+π/4)