因式分解:(x^3-12x)^2-256

来源:学生作业帮助网 编辑:六六作业网 时间:2024/05/10 08:18:32
因式分解:(x^3-12x)^2-256因式分解:(x^3-12x)^2-256因式分解:(x^3-12x)^2-256:(x^3-12x)^2-256=(x³-12x+16)(x³

因式分解:(x^3-12x)^2-256
因式分解:(x^3-12x)^2-256

因式分解:(x^3-12x)^2-256
:(x^3-12x)^2-256
=(x³-12x+16)(x³-12x-16)
=(x³+4x²-4x²-12x+16)(x³-4x²+4x²-12x-16)
=[x²(x+4)-4(x²+3x-4)][x²(x-4)+4(x²-3x-4)]
=[(x+4)x²-4(x+4)(x-1)][(x-4)x²+4(x+1)(x-4)]
=(x+4)(x²-4x+4)(x-4)(x²+4x+4)
=(x+4)(x-2)²(x-4)(x+2)²

(x^3-12x)^2-256
=(x^3-12x+16)(x^3-12x-16)

(x^3-12x)^2-256
=(x³-12x+16)(x³-12x-16)
=(x³+4x²-4x²-12x+16)(x³-4x²+4x²-12x-16) 这一步注意自己多试一下
=[x²(x+4)-4(x²+3x-4)][x²(x-4)+4(x...

全部展开

(x^3-12x)^2-256
=(x³-12x+16)(x³-12x-16)
=(x³+4x²-4x²-12x+16)(x³-4x²+4x²-12x-16) 这一步注意自己多试一下
=[x²(x+4)-4(x²+3x-4)][x²(x-4)+4(x²-3x-4)]
=[(x+4)x²-4(x+4)(x-1)][(x-4)x²+4(x+1)(x-4)]
=(x+4)(x²-4x+4)(x-4)(x²+4x+4)
=(x+4)(x-2)²(x-4)(x+2)²

收起


(x^3-12x)^2-256
=(x^3-12x)^2-16^2
=(x³-12x+16)(x³-12x-16)
=(x³+4x²-4x²-12x+16)(x³-4x²+4x²-12x-16)
=[x²(x+4)-4(x²+3x-4)][x²(x...

全部展开


(x^3-12x)^2-256
=(x^3-12x)^2-16^2
=(x³-12x+16)(x³-12x-16)
=(x³+4x²-4x²-12x+16)(x³-4x²+4x²-12x-16)
=[x²(x+4)-4(x²+3x-4)][x²(x-4)+4(x²-3x-4)]
=[(x+4)x²-4(x+4)(x-1)][(x-4)x²+4(x+1)(x-4)]
=[(x+4)x^2-(x+4)(4x-4)][(x-4)x²+4(x+1)(x-4)]
=(x+4)(x²-4x+4)(x-4)(x²+4x+4)
=(x+4)(x-4)(x-2)²(x+2)²

收起

原式=(x^3-12x+16)(x^3-12x-16)
=(x-2)(x^2+2x-8)(x+2)(x^2-2x-8)
=(x-2)(x+4)(x-2)(x+2)(x-4)(x+2)
=(x-2)^2(x+2)^2(x+4)(x-4)