sin(π/3+15°)=
来源：学生作业帮助网 编辑：六六作业网 时间：2024/05/14 22:06:02
sin(π/3+15°)=sin(π/3+15°)=sin(π/3+15°)=sin(π/3+15°)=sin(π/3+π/12)=sin(5π/12)=sin(π/4+π/6)=snπ/4cosπ/
sin(π/3+15°)=
sin(π/3+15°)=
sin(π/3+15°)=
sin(π/3+15°)
=sin(π/3+π/12)
=sin(5π/12)
=sin(π/4+π/6)
=snπ/4cosπ/6+cosπ/4sinπ/6
=(√6+√2)/4
sin(π/3+15°)= sin(60°+15°)= sin75°=sin(30°+45°)=sin30°cos45°+ cos30°sin45°=（根号2+根号6 ）/4
sin(π/3+15°)=
化简sin(α+β)+sin(α-β)+2sinαsin(3π/2-β)=
sin（-19π/6）=；sin（-16π/3）=；cos（-79π/6）=；tan（-26π/3）=；sin（15π/4）=；cos（-60°）-sin（-210°）=?
sin²1°+sin²2°+sin²3°+……+sin²87°+sin²88°+sin²89°=
sin²1°+sin²2°+sin²3°+...+sin²88°+sin²89°+sin²90°=等于多少?
计算：sin（3π /4 ) +cos (2π /3) - sin 150° + cos135°=?
sin π/8 sin 3π/8=
2sin(α+π/3）=sinα+______
2sin π/6 =sin π/3,吗,求解释,还有-sin π/6=sin- π/6吗
sin (-1300°) 为什么答案是sin40°呢 原式=-sin(1300°)=-sin(360×3+220）= -(-sin 220)= sin220 sin(π+a）= - sina 请问我这步骤对么?
sin²1°+sin²2°+sin²3°……sin²89°=?
sin²1°+sin²2°+sin²3°……sin²89°=
求sin²1°+sin²2°+sin²3°……sin²89°=?
sin²1°+sin²2°+sin²3°+.+sin²89°= -1为什么?
sin²1°+sin²2°+sin²3°.+sin²89°=
已知sin(3π-α)=-2sin(π/2+α)则sinαcosα
sin²1°+sin²2°+sin²3°+...+sin²88°+sin²89°=
已知sinα=-0.4,求下列三角函数值 sin（-α） sin（3π-α） sin（α-π） sin（α-10π）