100+(x-100)/10=200+[x-200-100-(x-100)/10]/10
来源：学生作业帮助网 编辑：六六作业网 时间：2024/05/11 00:32:03
100+(x-100)/10=200+[x-200-100-(x-100)/10]/10100+(x-100)/10=200+[x-200-100-(x-100)/10]/10100+(x-100)/
100+(x-100)/10=200+[x-200-100-(x-100)/10]/10
100+(x-100)/10=200+[x-200-100-(x-100)/10]/10
100+(x-100)/10=200+[x-200-100-(x-100)/10]/10
100+(x-100)/10=200+[x-200-100-(x-100)/10]/10
100+10x-1000=200+[x-300-10x+1000]/10
10x-900=200+(700-9x)/10
10x-1100=70-90x
100x=1170
x=11.7
100+(x-100)/10=200+[x-200-100-(x-100)/10]/10
90+x/10=200+[x-300-x/10+10]*1/10
90+x/10=200+9x/100-29
x/100=81
x=8100
（X+X)+(X-X)+(X*X)+(X/X)=100
X+X-10+X+8=100
求x:x(10^x)=100
100×2x+10x+3x+216=100×3x+10×2x+x
100(X - 2) + 10X + 2X = 100*2X + 10X + X - 2 - 495
200x+170(70-x)+100(40-x)+x-10=
100(x+4)+10x+(x+2)=21[10x+(x+2)]
求x 的值.x +3.5x =9.9;4.25x -x =4.55;10x -2.7x =58.4;6.8x +3.2x =100
一道一元一次方程,[100x+10(x-2)+24-x-(x-2)]-(10x+x)=100[24-x-(x-2)]+10(x-2)+x[100x+10(x-2)+24-x-(x-2)]-(10x+x)=100[24-x-(x-2)]+10(x-2)+x
100X的平方+10（X+3)+X=202+25(X+3) 求X
X+X+X+X+X+X+100X=1690 问：X等于多少
请帮我解一个方程 写出每一步 2[100x+10(x+1)+2x]-49=200x+10(x+1)+x
100+1/10(X-100)=200+1/10[X-(100+1/10(X-100) - 200]
100+(x-100)/10=200+[x-200-100-(x-100)/10]/10
30%x+10%(100-x)=100*x的过程
19-200x+100x*x=0
10/150x-1=10/100x.求x
100/x+1/2=150/(x+10) x=?