函数y=(2x+3)/(x-1)(x

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函数y=(2x+3)/(x-1)(x函数y=(2x+3)/(x-1)(x函数y=(2x+3)/(x-1)(x由y=(2x+3)/(x-1)移项得y(x-1)-(2x+3)=0整理得x(y-2)-(y+

函数y=(2x+3)/(x-1)(x
函数y=(2x+3)/(x-1)(x

函数y=(2x+3)/(x-1)(x
由y=(2x+3)/(x-1)移项得
y(x-1)-(2x+3)=0
整理得x(y-2)-(y+3)=0
再移项得x=(y+3)/(y-2)
解得y≠2
又x

-3到正无穷