已知x+y=-1,xy=-2,求代数式-5(x+y)+(x-y)+x(xy+y)的值

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已知x+y=-1,xy=-2,求代数式-5(x+y)+(x-y)+x(xy+y)的值已知x+y=-1,xy=-2,求代数式-5(x+y)+(x-y)+x(xy+y)的值已知x+y=-1,xy=-2,求

已知x+y=-1,xy=-2,求代数式-5(x+y)+(x-y)+x(xy+y)的值
已知x+y=-1,xy=-2,求代数式-5(x+y)+(x-y)+x(xy+y)的值

已知x+y=-1,xy=-2,求代数式-5(x+y)+(x-y)+x(xy+y)的值
答:
x+y=-1,xy=-2
-5(x+y)+(x-y)+x(xy+y)
=-5x-5y+x-y+xy(x+1)
=-4x-6y+(-2)(x+1)
=-4x-6y-2x-2
=-6x-6y-2
=-6(x+y)-2
=-6×(-1)-2
=6-2
=4