先化简后求值6x^2-(2x+1)(3x-2)+(x+3)(x-3),其中x=1/2

来源:学生作业帮助网 编辑:六六作业网 时间:2024/05/27 15:31:23
先化简后求值6x^2-(2x+1)(3x-2)+(x+3)(x-3),其中x=1/2先化简后求值6x^2-(2x+1)(3x-2)+(x+3)(x-3),其中x=1/2先化简后求值6x^2-(2x+1

先化简后求值6x^2-(2x+1)(3x-2)+(x+3)(x-3),其中x=1/2
先化简后求值6x^2-(2x+1)(3x-2)+(x+3)(x-3),其中x=1/2

先化简后求值6x^2-(2x+1)(3x-2)+(x+3)(x-3),其中x=1/2
6x^2-(2x+1)(3x-2)+(x+3)(x-3),
=6x^2-(6x^2-x-2)+x²-9
=6x^2-6x^2+x+2+x^2-9
=x^2+x-7
x=1/2
=1/4+1/2-7
=-25/4