设函数f(x)=sin(2x+φ)(-π

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设函数f(x)=sin(2x+φ)(-π设函数f(x)=sin(2x+φ)(-π设函数f(x)=sin(2x+φ)(-π-3π/4由sin对称性可知f(x)=-1或1此时2x+φ=π/2或-π/2+k

设函数f(x)=sin(2x+φ)(-π
设函数f(x)=sin(2x+φ)(-π

设函数f(x)=sin(2x+φ)(-π
-3π/4
由sin对称性可知
f(x)= -1 或 1
此时 2x + φ = π/2 或 -π/2 +kπ(k=0、±1、±2…)
又由于(-π

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