(1-x)dx-(1+y)dy=0求通解

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(1-x)dx-(1+y)dy=0求通解(1-x)dx-(1+y)dy=0求通解(1-x)dx-(1+y)dy=0求通解(1+y)dx-(1-x)dy=0(1+y)dx=(1-x)dy[1/(1-x)

(1-x)dx-(1+y)dy=0求通解
(1-x)dx-(1+y)dy=0求通解

(1-x)dx-(1+y)dy=0求通解
(1 + y) dx - (1 - x) dy = 0(1 + y) dx = (1 - x) dy[1/(1 - x)]dx =[1 /(1 + y)]dyd(ln(1 - x))=d(ln(1 + y))ln(1 - x) + C1 = ln(1 + y) (C1为任意实数)1 + y = e^[ln(1 - x) + C1]y = C*(1 - x) - 1 (C为任意实数)