16x^2-361=0 (x-1)^2=25
来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/01 06:54:37
16x^2-361=0(x-1)^2=2516x^2-361=0(x-1)^2=2516x^2-361=0(x-1)^2=2516x^2-361=0 16x^2=361x^2=361/16x
16x^2-361=0 (x-1)^2=25
16x^2-361=0 (x-1)^2=25
16x^2-361=0 (x-1)^2=25
16x^2-361=0
16x^2=361
x^2=361/16
x1=19/4 x2=-19/4
(x-1)^2=25
x-1=±5
x=1±5
x1=6 x2=-4
(x)-2x·x-x-2x+1=0求x的值,
一个“整式的乘法”的问题请先阅读下列解题过程,再仿做下面的问题.已知X*X + X - 1=0,求X*X*X + 2*X*X + 3的值.解X*X*X + 2X*X +3=X*X*X +X*X -X +X*X +X +3=X{X*X +X -1} +X*X +X -1 +4=0+0+4=4+ x + X*X + X*X*X=0.+ X*X + X*X*X
先化简再求值(x-1/x-x-2/x+1)/(2x²-x/x²+2x+1)且x²-x-1 =0
(X-3分之x-1-x分之x-4)除以x的平方+3x分之(x+3)(x-2),其中(x-1)(x-2)=0
如果X*X--1=0,那么X*X*X+2*X*X+2008=几?
已知x*x+x-1=0 求x*x*x-2x+11=?
已知x*x+x-1=0求x*x*x-2x+2010的值
请问这道题咋做 :(x)X (x+1) X (x+2) X (x+3) =360
x^4+x^3+x^2+x+1=0,x^2006+x^2005+x^2004+x^2003+x^2002
f(x)=(x+1)ln(x+1)+m(x^2+2x) x>=0时,f(x)
matlab解数值分析题p=(x-1)*(x-2)*(x-3)*(x-4)*(x-5)*(x-6)*(x-7)*(x-8)*(x-9)*(x-10)*(x-11)*(x-12)*(x-13)*(x-14)*(x-15)*(x-16)*(x-17)*(x-18)*(x-19)*(x-20)解为1,2,3……,20取多个非常小的数用软件工具求解方程p(x)+n*x^19=0,并
f(x)=x/(1+x) x>=0 f1(X)=f(X) fn(X)=fn-1[fn-1(x)]求fn(x)证明:f1(X)+2f2(X)+3f3(x)+……+nfn(X)
已知f(x)= -x^2-2x g(x)= 分段函数 x+1/4x(x>0),x+1(x
判断函数奇偶性,快,f(x)=a(x属于R)f(x)=x^2 (1-x) ,x大于等于0x^2 (1+x) ,x
已知X²-3x-2=0,求 2x-1 x-1 ----- ÷ -------- 的值 (x- x) x²-2x不能先求X
(1-3/x+2)÷x-1/x²+2x-x/x+1,其中x满足x²-x-1=0
(2x-2)(x-1)=0 x(x-5)=5x-10
画出f(x)={(x+1 x≥0) (x-2 x