已知a+b+c=0,求a3+a2c-abc+b2c+b3=?

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已知a+b+c=0,求a3+a2c-abc+b2c+b3=?已知a+b+c=0,求a3+a2c-abc+b2c+b3=?已知a+b+c=0,求a3+a2c-abc+b2c+b3=?=(a^3+b^3)

已知a+b+c=0,求a3+a2c-abc+b2c+b3=?
已知a+b+c=0,求a3+a2c-abc+b2c+b3=?

已知a+b+c=0,求a3+a2c-abc+b2c+b3=?
=(a^3+b^3)+(a^2c+b^2cc-abc)
=(a+b)(a^2-ab+b^2)+c(a^2-ab+b^2)
=(a+b+c)(a^2-ab+b^2)
a+b+c=0.所以=0