当x等于x的相反数时,分式(x^2-1)[(x+1)/(x-1)+(x-1)/(x+1)-(x^2-1)/1]=?

来源:学生作业帮助网 编辑:六六作业网 时间:2024/05/13 02:30:05
当x等于x的相反数时,分式(x^2-1)[(x+1)/(x-1)+(x-1)/(x+1)-(x^2-1)/1]=?当x等于x的相反数时,分式(x^2-1)[(x+1)/(x-1)+(x-1)/(x+1

当x等于x的相反数时,分式(x^2-1)[(x+1)/(x-1)+(x-1)/(x+1)-(x^2-1)/1]=?
当x等于x的相反数时,分式(x^2-1)[(x+1)/(x-1)+(x-1)/(x+1)-(x^2-1)/1]=?

当x等于x的相反数时,分式(x^2-1)[(x+1)/(x-1)+(x-1)/(x+1)-(x^2-1)/1]=?
相反数等于本身的只有0,
(x^2-1)[(x+1)/(x-1)+(x-1)/(x+1)-(x^2-1)/1]
=-1×(-1-1+1)
=1

当x等于x的相反数时,x等于且只等于0,代入得
-1*[-1-1+1]=1