n趋向于无穷,[√(n^2+1)+n]^2/(n^6+1)^3/2.极限等于4是怎么算出来的啊?
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n趋向于无穷,[√(n^2+1)+n]^2/(n^6+1)^3/2.极限等于4是怎么算出来的啊?n趋向于无穷,[√(n^2+1)+n]^2/(n^6+1)^3/2.极限等于4是怎么算出来的啊?n趋向于
n趋向于无穷,[√(n^2+1)+n]^2/(n^6+1)^3/2.极限等于4是怎么算出来的啊?
n趋向于无穷,[√(n^2+1)+n]^2/(n^6+1)^3/2.极限等于4是怎么算出来的啊?
n趋向于无穷,[√(n^2+1)+n]^2/(n^6+1)^3/2.极限等于4是怎么算出来的啊?
解答见本人中心的\x0d(本题应该有抄写错误)\x0d
恐怖。。。高二的飘过
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