(y+3)(1-3y)=1+2y^2-1/2^-2 =多少

来源:学生作业帮助网 编辑:六六作业网 时间:2024/05/03 16:05:42
(y+3)(1-3y)=1+2y^2-1/2^-2=多少(y+3)(1-3y)=1+2y^2-1/2^-2=多少(y+3)(1-3y)=1+2y^2-1/2^-2=多少-1/2^-2=-4(y+3)(

(y+3)(1-3y)=1+2y^2-1/2^-2 =多少
(y+3)(1-3y)=1+2y^2
-1/2^-2 =多少

(y+3)(1-3y)=1+2y^2-1/2^-2 =多少
-1/2^-2 =-4
(y+3)(1-3y)=1+2y^2
左边=-3y^2-8y+3
所以原式为
-3y^2-8y+3=1+2y^2
移项,整理得
5y^2+8y-2=0

(y+3)(1-3y)=1+2y^2
-3y²-8y+3=1+2y²
5y²+8y-2=0
y=(-8±2√26)/10
y1=(-4+√26)/5
y2=(-4-√26)/5
-1/2^(-2)=-4

-1/2^-2 这式子有问题 至于上面的问题 -8y-3y^2+3=1+2y^2
(5y^2)+8y-2=0
y=(-4+(26)^(1/2))/5 或 y=(-4-(26)^(1/2))/5