∫[(sin^2)x]dx求不定积分
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∫[(sin^2)x]dx求不定积分∫[(sin^2)x]dx求不定积分∫[(sin^2)x]dx求不定积分∫[(sin^2)x]dx=1/2*∫(1-cos(2x))dx=1/2*(x-1/2*si
∫[(sin^2)x]dx求不定积分
∫[(sin^2)x]dx求不定积分
∫[(sin^2)x]dx求不定积分
∫[(sin^2)x]dx
=1/2*∫(1-cos(2x))dx
=1/2*(x-1/2*sin(2x))+C
=x/2-sin(2x)/4+C
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