已知x+1/x=2,求(x^2008+ x^-2008 -2)/(x^2009 +x^-2009)

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已知x+1/x=2,求(x^2008+x^-2008-2)/(x^2009+x^-2009)已知x+1/x=2,求(x^2008+x^-2008-2)/(x^2009+x^-2009)已知x+1/x=

已知x+1/x=2,求(x^2008+ x^-2008 -2)/(x^2009 +x^-2009)
已知x+1/x=2,求(x^2008+ x^-2008 -2)/(x^2009 +x^-2009)

已知x+1/x=2,求(x^2008+ x^-2008 -2)/(x^2009 +x^-2009)
x+1/x=2 那么x=1 仅此一解
(x^2008+ x^-2008 -2)/(x^2009 +x^-2009)=0/2=0