lim(x→0)[(1/x)-(1/ln1+x)]

lim→0+ lnx ln(1+X) 求极限lim Ln(1+x) /x > .< x→0 lim(x→0)tan(x)ln(1+x)=? 对数函数的极限 lim(x→0) [ln(1+x)-ln(1-x)]/x lim(x→0)(cosx)^(1/ln(1+x^2)) lim(x→0)ln（x^2+1）等于 lim(x趋于0+)(ln(xln a)ln(ln ax/ln(x/a))),其中a>1 lim{ln[1+arcsinx]/sinx} x→0 lim(x→0) (ln cosx)/[ln(1+x^2)] 等于多少? lim(x→∞)x[ln(x-1)-lnx] lim(1/ln(1+x)-1/x) x趋于0 lim(x->0)ln(1+2x)/e^x-1 x趋向0 lim [ ln (1-x) / (e ^ x-1 ) ] lim(x->0)(ln(1+x)-x)/(cosx-1)=? lim ln(1+x)^ 1/x x趋近于0 lim(x趋于0）(ln(1+x)^1/x) lim(ln(1+x)/x) x趋向0 lim(x趋向0)ln(1+sin x)/x^2