等差数列中a1=1 an=-512 Sn=-1022求公差d

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等差数列中a1=1an=-512Sn=-1022求公差d等差数列中a1=1an=-512Sn=-1022求公差d等差数列中a1=1an=-512Sn=-1022求公差d-171Sn=[n*(a1+an

等差数列中a1=1 an=-512 Sn=-1022求公差d
等差数列中a1=1 an=-512 Sn=-1022求公差d

等差数列中a1=1 an=-512 Sn=-1022求公差d
-171
Sn=[n*(a1+an)]/2
带进去得:n=4
a4=a1+3d
d=[a4-a1]/3=-513/3=-171