复数(根号3 -i)/(1+根号3i)=

来源:学生作业帮助网 编辑:六六作业网 时间:2024/05/25 05:43:13
复数(根号3-i)/(1+根号3i)=复数(根号3-i)/(1+根号3i)=复数(根号3-i)/(1+根号3i)=(√3-i)/(1+√3i)=(√3-i)(1-√3i)/(1+√3i)(1-√3i)

复数(根号3 -i)/(1+根号3i)=
复数(根号3 -i)/(1+根号3i)=

复数(根号3 -i)/(1+根号3i)=
(√3 -i)/(1+√3i)
=(√3 -i)(1-√3i)/(1+√3i)(1-√3i)
=(√3-√3-i-3i ) / ( 1 + 3 )
= - i
(1+根号3i)/(根号3 -i) 刚好为上面的倒数
因此=1/(-i) = i / (-i*i) = i
o(∩_∩)o

(根号3 -i)/(1+根号3i)
=(根号3 -i)(1-根号3i)/(1+根号3i)(1-根号3i)
=-4i/10
=-2i/5

i