MOV AX,789FH MOV CX,16 MOV DL,0 L1:ROL AX,1 JNC NEXT INC DL NEXT:LOOP L1 INT 3DL= ________,AX=________,CX= ________,CF= ________

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MOVAX,789FHMOVCX,16MOVDL,0L1:ROLAX,1JNCNEXTINCDLNEXT:LOOPL1INT3DL=________,AX=________,CX=________,C

MOV AX,789FH MOV CX,16 MOV DL,0 L1:ROL AX,1 JNC NEXT INC DL NEXT:LOOP L1 INT 3DL= ________,AX=________,CX= ________,CF= ________
MOV AX,789FH MOV CX,16 MOV DL,0 L1:ROL AX,1 JNC NEXT INC DL NEXT:LOOP L1 INT 3
DL= ________,AX=________,CX= ________,CF= ________

MOV AX,789FH MOV CX,16 MOV DL,0 L1:ROL AX,1 JNC NEXT INC DL NEXT:LOOP L1 INT 3DL= ________,AX=________,CX= ________,CF= ________
首先说明int 3 是Windows系统向的调试软中断,相当于一个断点.即该指令处设置了一个断点,很可能是程序中使用 __asm__( int 3) 插入了一个调试中断.
DL=10 DL实际上是AX中含1的个数,因为AX=0111100010011111
AX=789FH 因为移位16次之后AX值没有变化
CX=0
CF=1 CF实际上是AX中最低位D0的值

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