(4xy2-2x2y)-( )=x3-2x2y+4xy2+y3．

(4xy2-2x2y)-( )=x3-2x2y+4xy2+y3． x3-2x2y+xy2-x 因式分解:x3-2x2y+xy2 3x2y+xy2-[2xy2-4x2y+(x2y-2xy2)] (X3-2x2y+xy2)÷（x3-xy2）要求约分 分解因式:X3+2X2Y+2XY2+Y3= x3+2x2y+2xy2+y3因式分解 分解因式：x3+xy2－2x2y 若m=x3-3x2y+2xy2+3y2 n=x3-2x2y+xy2-5y3,则2x3-7x2y+5xy2+14y2等于( )若m=x3-3x2y+2xy2+3y2 n=x3-2x2y+xy2-5y3,则2x3-7x2y+5xy2+14y2等于( )空里用字母表示 5xy2-【3xy2-(4xy2-2x2y)】+2x2y】+2x2y-xy2 化简,再求值 x.y取何值时,代数(x3y+3x2y-5xy2+6y3)+(y3+2xy2+x2y-2x3)-(4x2y-x3-3xy2+7y3).y取何值时，代数（x3y+3x2y-5xy2+6y3）+（y3+2xy2+x2y-2x3）-（4x2y-x3-3xy2+7y3）的值都是常数? x3+x2y-xy2-y3= 试说明代数式(x3+3x2y-4xy2+6y3)-(2x3-x2y-xy2-y3-1)+(x34x2y+3xy2-7y3)的值与xy取值无关 若x3+y3=1000,x2y－xy=－496,则（x3－y3）+（4xy2－2x2y）－2（xy2－y3）= ---- 设A=x3+3x2y-2xy2+4y3-1,B=y3-xy2+x2y-2x3,C=-x3+4x2y-3xy2+5y3+5.求证：不论x,y取任何有理数,多项式A+B-C的值总等于一个常数,并求出这个常数 试说明:无论x,y取何值时,代数式(x3+3x2y-5+6y3)+(y3+2xy2+x2y-2x3)-(4x2y-x3-3xy2+7y2)的值是常数.要具体过程,注意格式 x3-4xy2-2x2y+8y因式分解 正确的秒批 因式分解：-x3-4xy2+4x2y