y=(2x*x-2x+3)/(x*x-x+1),求值域?
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y=(2x*x-2x+3)/(x*x-x+1),求值域?y=(2x*x-2x+3)/(x*x-x+1),求值域?y=(2x*x-2x+3)/(x*x-x+1),求值域?y=2x2;-4x+2-3=2(
y=(2x*x-2x+3)/(x*x-x+1),求值域?
y=(2x*x-2x+3)/(x*x-x+1),求值域?
y=(2x*x-2x+3)/(x*x-x+1),求值域?
y=2x2;-4x+2-3 =2(x-1)2;-3 0≤x≤3 -1≤x-1≤2 所以0≤(x-1)2;≤4 0≤2(x-1)2;≤8 -3≤2(x-1)2;-3≤5 所以值域[-3,5]
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