lim(x→∞)[(X^2+2x+5)/(3x^2-x+1) =

lim xsin(2/x) x→∞ Lim [x^2/(x^2-1)]^x (x→∞) lim(1+x/x)2x (x→∞) lim(x→∞)[(X^2+2x+5)/(3x^2-x+1) = 1.lim x->∞ （2x/x^2+1)*cosx 2..lim x->∞{ [(x^2-x)arctanx]/x^3-x-5}3..lim x->0 （e^x-e^-x-2x)/(x-sinx) 4..lim x->0 (sinx-x)/(x^3) 5..lim x->0 (x^2*tanx)/(x-tanx) 6..lim x->0 (1+3/x)^2x 7..lim x->0 (1+2x)^(3/sinx) 8.lim x->∞ (x/1+x)^(x-3) 9..li lim(x)lim(x→∞) [(x-1)/(x+1)]^2x 为什么 lim(x->∞) {[(-2)/(x+1)]*2x} = -4 lim x→∞ (x+sin 2x)/2 lim(x→∞)(1-2/x)^2x x/2-1lim(1-2/x)x→∞ lim x→∞(2x+1)/(3x-4) lim(x→+∞) (2/π arctan X)^X lim(x→∞)(1-2/x) (x+1)次方 lim x→∞ x-1/x^2 lim x→∞(1-2/x)^x= lim(x→∞)[1+(1/x)]^x/2 求lim(√x^2+1)-x x→-∞ 烦人的数学微积分1、lim(x→0)Sin3x/Sin2x2、lim(x→0)x/3*Sin3x3、lim(x→0)[Xsin(3/x)+(tanx/2x)]4、lim(x→3)Sin(x-3)/(X^2-X-6)5、lim(x→∞)[1+(1/2x)^x6、lim(x→∞)(x+3/x)^x7、lim(x→0)（1-x/2)^1/x+118、求下列函数的间断 lim(x→0) (3x^2-5x+2),