4.P:x^2-(3a-1)x+(2a^2-a)

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4.P:x^2-(3a-1)x+(2a^2-a)4.P:x^2-(3a-1)x+(2a^2-a)4.P:x^2-(3a-1)x+(2a^2-a)q(x-1)(x-3)1p(x-a)[x-(2a-1)]

4.P:x^2-(3a-1)x+(2a^2-a)
4.P:x^2-(3a-1)x+(2a^2-a)<0,q:x^2-4x+3<0,命题p可推出命题q,求a的范围

4.P:x^2-(3a-1)x+(2a^2-a)
q
(x-1)(x-3)<0
1p
(x-a)[x-(2a-1)]<0
命题p可推出命题q
则p是q的子集
a<1,则a>2a-1
2a-1要满足1所以2a-1>=1,a<=3
1<=a<=3,不满足a<1
a=1,则(x-1)²<0,不成立,p是空集,也可以
a>1,则a>2a-1
a要满足1所以a>=1,2a-1<=3
所以1综上
1≤a≤2