已知x,y满足{x>=1,x+y

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已知x,y满足{x>=1,x+y已知x,y满足{x>=1,x+y已知x,y满足{x>=1,x+y解直角坐标系中画出x>=1x+yaax+by+c=0过(1,-1),(3,1)所以y=x-2所以(a+b

已知x,y满足{x>=1,x+y
已知x,y满足{x>=1,x+y

已知x,y满足{x>=1,x+y
解 直角坐标系中画出 x>=1 x+y

a

ax+by+c=0过(1,-1),(3,1)所以y=x-2 所以(a+b+c)/a=-2