∫1/sin^4x dx
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∫1/sin^4xdx∫1/sin^4xdx∫1/sin^4xdx∫1/sin⁴xdx=∫csc⁴xdx=∫csc²xd(-cotx)=-∫(1+cot²x
∫1/sin^4x dx
∫1/sin^4x dx
∫1/sin^4x dx
∫ 1/sin⁴x dx
= ∫ csc⁴x dx
= ∫ csc²x d(- cotx)
= - ∫ (1 + cot²x) d(cotx)
= - (cotx + 1/3 * cot³x) + C
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