f(x)=a(cos^2 x+sin xcos x)+b,求当a
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f(x)=a(cos^2x+sinxcosx)+b,求当af(x)=a(cos^2x+sinxcosx)+b,求当af(x)=a(cos^2x+sinxcosx)+b,求当a∵f(x)=a[cos^2
f(x)=a(cos^2 x+sin xcos x)+b,求当a
f(x)=a(cos^2 x+sin xcos x)+b,求当a
f(x)=a(cos^2 x+sin xcos x)+b,求当a
∵f(x)=a[cos^2(x)+sinxcosx]+b
=a[(1+cos2x)/2+(1/2)(2sinxcosx)]+b
=a[(1/2)sin2x+(1/2)cos2x+1/2]+b
=a[(1/2)(sin2x+cos2x)]+(a+2b)/2
=(√2a/2)sin(2x+π/4)+(a+2b)/2
∵x∈[0,π/2]
∴2x+π/4∈[π/4,5π/4]
∴sin(2x+π/4)∈[-√2/2,1]
∵a
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