若sin(6分之π-角二法)=a,则cos(3分之2π-角二法)=?

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若sin(6分之π-角二法)=a,则cos(3分之2π-角二法)=?若sin(6分之π-角二法)=a,则cos(3分之2π-角二法)=?若sin(6分之π-角二法)=a,则cos(3分之2π-角二法)

若sin(6分之π-角二法)=a,则cos(3分之2π-角二法)=?
若sin(6分之π-角二法)=a,则cos(3分之2π-角二法)=?

若sin(6分之π-角二法)=a,则cos(3分之2π-角二法)=?
sin(π/6-α)=a
cos(2π/3-α)=-cos(π-2π/3+α)=-cos(π/3+α)=-cos(π/2-(π/6-α))=-sin(π/6-α)=-a