已知x^2-xy=14,xy-y^2=-11,求x^2-2xy+y^2的值
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已知x^2-xy=14,xy-y^2=-11,求x^2-2xy+y^2的值已知x^2-xy=14,xy-y^2=-11,求x^2-2xy+y^2的值已知x^2-xy=14,xy-y^2=-11,求x^
已知x^2-xy=14,xy-y^2=-11,求x^2-2xy+y^2的值
已知x^2-xy=14,xy-y^2=-11,求x^2-2xy+y^2的值
已知x^2-xy=14,xy-y^2=-11,求x^2-2xy+y^2的值
x^2-xy=14,(1) xy-y^2=-11,(2)
(1)-(2)得：x^2-2xy+y^2=14-(-11)=25
x^2-xy=14,
xy-y^2=-11
两式相减得
x^2-2xy+y^2=25
25
x^2-xy=14,xy-y^2=-11,两式想减得到x^2-2xy+y^2=25
x^2-xy=14 为一式
xy-y^2=-11为二式
一式减去二式
得
x^2-2xy+y^2=14-（-11）=25
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