dx/(4x-x^2)求不定积分
来源：学生作业帮助网 编辑：六六作业网 时间：2024/05/10 07:29:51
dx/(4x-x^2)求不定积分dx/(4x-x^2)求不定积分dx/(4x-x^2)求不定积分∫dx/(4x-x^2)=∫dx/[x(4-x)]=(1/4)∫[(4-x)+x]/[x/(4-x)]d
dx/(4x-x^2)求不定积分
dx/(4x-x^2)求不定积分
dx/(4x-x^2)求不定积分
∫ dx/(4x - x^2)
= ∫ dx/[x(4 - x)]
= (1/4)∫ [(4 - x) + x]/[x/(4 - x)] dx
= (1/4)∫ [1/x + 1/(4 - x)] dx
= (1/4)[ln(x) - ln(4 - x)] + C
= (1/4)ln[x/(4 - x)] + C
dx/(4x-x^2)求不定积分
求不定积分dx/4一x^2
求不定积分dx/x^2
求dx/[(x-1)(x^2+4x+9)]不定积分?
求不定积分x( sin^2)x dx
求不定积分dx/x^2-x+6
求不定积分 ∫x/(x^2)dx
求不定积分∫(x^2-2x-4)dx
求不定积分根号4-x^2/x^2dx
求不定积分∫1/(x^2+4x+5)dx.
求不定积分 dx/(x^4 *根号下1+x^2)
∫x*根号4x^2-1 dx 求不定积分
∫ x/（x^2+4） dx 求不定积分
求不定积分∫(tan^2x+tan^4x)dx
∫1/(x^2-4x+3)dx,求不定积分,
求不定积分∫(x^2/(1+x^4))dx
求不定积分 ∫ [(x^4)/(1+x^2)]dx=
求不定积分∫x^2/(1-x^4)dx