x2-5x-2001=0,则x-2分之(x-2)^3-(x-1)^2+1=?如题

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x2-5x-2001=0,则x-2分之(x-2)^3-(x-1)^2+1=?如题x2-5x-2001=0,则x-2分之(x-2)^3-(x-1)^2+1=?如题x2-5x-2001=0,则x-2分之(

x2-5x-2001=0,则x-2分之(x-2)^3-(x-1)^2+1=?如题
x2-5x-2001=0,则x-2分之(x-2)^3-(x-1)^2+1=?
如题

x2-5x-2001=0,则x-2分之(x-2)^3-(x-1)^2+1=?如题
卡布奇诺飒:
∵x^2-5x-2001=0
∴x^2-5x=2001
[(x-2)^3-(x-1)^2+1]/(x-2)
=(x-2)^2-[(x-1)^2-1]/(x-2)
=x^2-4x+4-(x^2-2x)/(x-2)
=x^2-4x+4-[x(x-2)/(x-2)]
=x^2-4x+4-x
=x^2-5x+4
=2001+4
=2005