1/4+1/12+1/24+1/40.+1/19800
来源：学生作业帮助网 编辑：六六作业网 时间：2024/05/17 08:56:32
1/4+1/12+1/24+1/40.+1/198001/4+1/12+1/24+1/40.+1/198001/4+1/12+1/24+1/40.+1/19800An=1/2n(n+1)=0.5*((
1/4+1/12+1/24+1/40.+1/19800
1/4+1/12+1/24+1/40.+1/19800
1/4+1/12+1/24+1/40.+1/19800
An=1/2n(n+1)=0.5*((1/n)-(1/n+1))
Sn=0.5*(1-1/n+1)
An=1/19800得n=99
Sn=99/200
1/4+1/12+1/24+1/40.+1/19800
1,4,12,40.的通项公式
1,4,12,40.的通项公式
1/4+1/12+1/24+...+1/180 简便算法
1/4+1/12+1/24+1/40+1/84+1/112+1/144+1/180
巧算1/4+1/12+1/24+1/40+1/60+1/84+1/112
算24点1,4,10,12
(5/12+1/6-3/4)×(-24)
2,-4,12,1算24点
2,-4,12,1 24点游戏
2,—4,12,1 24点咋弄啊
x(1/12+1/24)=1
简算!4分之1+12分之1+24分之1+40分之1+60分之1
4分之1+1/12+1/24+1/40…+1/19800
1/4+1/12+1/24+1/40……+1/19800=?
4/1+12/1+24/1+40/1+.19800/1
如何巧算1/4+1/12+1/24+1/40+.+1/19800
1/4+1/12+1/24+1/40+……+1/19800=?