tx^2+(1-2t)x-1/2+t=0时x的值为多少

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tx^2+(1-2t)x-1/2+t=0时x的值为多少tx^2+(1-2t)x-1/2+t=0时x的值为多少tx^2+(1-2t)x-1/2+t=0时x的值为多少x1=(2t-1+(1-2t)^1/2

tx^2+(1-2t)x-1/2+t=0时x的值为多少
tx^2+(1-2t)x-1/2+t=0时x的值为多少

tx^2+(1-2t)x-1/2+t=0时x的值为多少
x1=(2t-1+(1-2t)^1/2)/2t
x2=(2t-1-(1-2t)^1/2)/2t