2^log2 (3) × log2 (1/8) + 2lg3

来源:学生作业帮助网 编辑:六六作业网 时间:2024/05/09 09:28:12
2^log2(3)×log2(1/8)+2lg32^log2(3)×log2(1/8)+2lg32^log2(3)×log2(1/8)+2lg3利用公式:a^loga(N)=N,loga(N^M)=M

2^log2 (3) × log2 (1/8) + 2lg3
2^log2 (3) × log2 (1/8) + 2lg3

2^log2 (3) × log2 (1/8) + 2lg3
利用公式:a^loga(N)=N,loga(N^M)=Mloga(N)
[2^log2(3)]×log2(1/8)+2lg3
=3×log2(2^-3)+2lg3
=3×(-3)+2lg3
=2lg3-9

2^log2(3)×log2(1/8)+2lg3=3×(-3)+2lg3
=2lg3-9

(log2(3)+3)(log2(3)-1)