若角a,b满足-π/2

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若角a,b满足-π/2若角a,b满足-π/2若角a,b满足-π/2-π/2所以-π/2-π/2所以-π相加-3π/2

若角a,b满足-π/2
若角a,b满足-π/2

若角a,b满足-π/2
-π/2所以-π/2<-b<π/2
-π/2所以-π<2a<π
相加
-3π/2<2a-b<3π/2