6xy2-9x2y-y3+y
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6xy2-9x2y-y3+y6xy2-9x2y-y3+y6xy2-9x2y-y3+y6xy²-9x²y-y³+y=y(6xy-9x²-y²+1)=y[
6xy2-9x2y-y3+y
6xy2-9x2y-y3+y
6xy2-9x2y-y3+y
6xy²-9x²y-y³+y
=y(6xy-9x²-y²+1)
=y[1-(9x²-6xy+y²)] 完全平方
=y[1-(3x-y)²] 平方差
=y[1-(3x-y)][1+(3x-y)]
=y(1-3x+y)(1+3x-y)
6xy2-9x2y-y3+y
因式分解:6xy2-9x2y-y3
x.y取何值时,代数(x3y+3x2y-5xy2+6y3)+(y3+2xy2+x2y-2x3)-(4x2y-x3-3xy2+7y3).y取何值时,代数(x3y+3x2y-5xy2+6y3)+(y3+2xy2+x2y-2x3)-(4x2y-x3-3xy2+7y3)的值都是常数?
已知X大于Y,试比较X3-X2y+XY2与X2Y-XY2+Y3的大小.
因式分解:x3-y3-x2y+xy2
x3+x2y-xy2-y3=
(4).9(x+y)2-4(x-y)2 (5).(x+y)2-4(x+y-1) (6).-x2y+2xy2-y3
试说明:无论x,y取何值时,代数式(x3+3x2y-5+6y3)+(y3+2xy2+x2y-2x3)-(4x2y-x3-3xy2+7y2)的值是常数.要具体过程,注意格式
试说明代数式(x3+3x2y-4xy2+6y3)-(2x3-x2y-xy2-y3-1)+(x34x2y+3xy2-7y3)的值与xy取值无关
先化简再求值:-2y3+(3xy2-x2y)-2(xy2-y3),其中|2x-2|+(y+1)2=0.
分解因式 x3+y3-x2y-xy2
x3-y3-x2y+xy2分解因式
分解因式x3-xy2+x2y-y3
x3+2x2y+2xy2+y3因式分解
x2+x2y-xy2-y3得值
4xy2-4x2y-y3因式分解
分解公因式,4xy2-4x2y-y3,
若x-y=5,xy=14,则x3-x2y+xy2-y3=?