f(x)=[log2(x/8)][log(1/2)(4/x)]值域令log(1/2)x=t∈[-3,1/2]

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f(x)=[log2(x/8)][log(1/2)(4/x)]值域令log(1/2)x=t∈[-3,1/2]f(x)=[log2(x/8)][log(1/2)(4/x)]值域令log(1/2)x=t∈

f(x)=[log2(x/8)][log(1/2)(4/x)]值域令log(1/2)x=t∈[-3,1/2]
f(x)=[log2(x/8)][log(1/2)(4/x)]值域
令log(1/2)x=t∈[-3,1/2]

f(x)=[log2(x/8)][log(1/2)(4/x)]值域令log(1/2)x=t∈[-3,1/2]
这是答案