已知1/a -1/b =3,则分式(2a+3ab-2b)/(a-2ab-b)=?

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已知1/a-1/b=3,则分式(2a+3ab-2b)/(a-2ab-b)=?已知1/a-1/b=3,则分式(2a+3ab-2b)/(a-2ab-b)=?已知1/a-1/b=3,则分式(2a+3ab-2

已知1/a -1/b =3,则分式(2a+3ab-2b)/(a-2ab-b)=?
已知1/a -1/b =3,则分式(2a+3ab-2b)/(a-2ab-b)=?

已知1/a -1/b =3,则分式(2a+3ab-2b)/(a-2ab-b)=?
∵1/a-a/b=3
∴(b-a)/ab=3
∴b-a=3ab
∴(2a+3ab-2b)/(a-2ab-b)
=[-2(b-a)+3ab]/[-(b-a)-2ab]
=[-6ab+3ab]/[-3ab-2ab]
=(-3ab)/(-5ab)
=3/5