如果|ab-2|+(1-b))^2=0,求1/ab+1/(a+1)(b+1)+.+1/(a+2007)(b+2007)

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如果|ab-2|+(1-b))^2=0,求1/ab+1/(a+1)(b+1)+.+1/(a+2007)(b+2007)如果|ab-2|+(1-b))^2=0,求1/ab+1/(a+1)(b+1)+.+

如果|ab-2|+(1-b))^2=0,求1/ab+1/(a+1)(b+1)+.+1/(a+2007)(b+2007)
如果|ab-2|+(1-b))^2=0,求1/ab+1/(a+1)(b+1)+.+1/(a+2007)(b+2007)

如果|ab-2|+(1-b))^2=0,求1/ab+1/(a+1)(b+1)+.+1/(a+2007)(b+2007)
|ab-2|+(1-b))^2=0
ab - 2 = 0
1 - b = 0
a = 2
b = 1
代入:1/ab+1/(a+1)(b+1)+.+1/(a+2007)(b+2007)
= 1/(1*2) +1/(2*3)+1/(3*4)+...+1/(2008*2009)
= 1- 1/2009=2008/2009

|ab-2|+(1-b))^2=0 ab-2=0 1-b=0 a=2 b=1 1/ab+1/(a+1)(b+1)+......+1/(a+2007)(b+2007)=1/1*2+1/2*3+..+1/2008*2009 =1-1/2009=2008/2009